目录

1.字符串反转2.每个单词的第一个字母大写3.字符串查找唯一元素4.重复打印字符串和列表n次5.列表生成6.变量交换7.字符串拆分为子字符串列表8.多个字符串组合为一个字符串9.检测字符串是否为回文10.统计列表中元素的次数11.判断两个字符串是否为Anagrams12.使用try-except-else-block模块13.使用枚举函数得到key/value对14.检查对象的内存使用情况15.合并字典16.计算执行一段代码所花费的时间17.列表展开18.列表采样19.数字化20.检查列表元素的唯一性

Python的可读性和简单性是其广受欢迎的两大原因，本文介绍20个常用的Python技巧来提高代码的可读性，并能帮助你节省大量时间，下面的技巧将在你的日常编码练习中非常实用。

1.字符串反转

使用Python切片反转字符串：

# Reversing a string using slicing
 
my_string = "ABCDE"
reversed_string = my_string[::-1]
 
print(reversed_string)
 
# Output
# EDCBA

2.每个单词的第一个字母大写

使用title函数方法：

my_string = "my name is chaitanya baweja"
 
# using the title() function of string class
new_string = my_string.title()
 
print(new_string)
 
# Output
# My Name Is Chaitanya Baweja

3. 字符串查找唯一元素

使用集合的概念查找字符串的唯一元素:

my_string = "aavvccccddddeee"
 
# converting the string to a set
temp_set = set(my_string)
 
# stitching set into a string using join
new_string = "".join(temp_set)
 
print(new_string)
 
# output
# cdvae

4.重复打印字符串和列表n次

你可以使用乘法符号（*）打印字符串或列表多次：

n = 3 # number of repetitions
 
my_string = "abcd"
my_list = [1,2,3]
 
print(my_string*n)
# abcdabcdabcd
 
print(my_list*n)
# [1,2,3,1,2,3,1,2,3]

5.列表生成

# Multiplying each element in a list by 2
 
original_list = [1,2,3,4]
 
new_list = [2*x for x in original_list]
 
print(new_list)
# [2,4,6,8]

6.变量交换

a = 1
b = 2
 
a, b = b, a
 
print(a) # 2
print(b) # 1

7.字符串拆分为子字符串列表

使用.split()函数：

string_1 = "My name is Chaitanya Baweja"
string_2 = "sample/ string 2"
 
# default separator " "
print(string_1.split())
# ["My", "name", "is", "Chaitanya", "Baweja"]
 
# defining separator as "/"
print(string_2.split("/"))
# ["sample", " string 2"]

8.多个字符串组合为一个字符串

list_of_strings = ["My", "name", "is", "Chaitanya", "Baweja"]
 
# Using join with the comma separator
print(",".join(list_of_strings))
 
# Output
# My,name,is,Chaitanya,Baweja

9.检测字符串是否为回文

my_string = "abcba"
 
if my_string == my_string[::-1]:
    print("palindrome")
else:
    print("not palindrome")
 
# Output
# palindrome

10. 统计列表中元素的次数

# finding frequency of each element in a list
from collections import Counter
 
my_list = ["a","a","b","b","b","c","d","d","d","d","d"]
count = Counter(my_list) # defining a counter object
 
print(count) # Of all elements
# Counter({"d": 5, "b": 3, "a": 2, "c": 1})
 
print(count["b"]) # of individual element
# 3
 
print(count.most_common(1)) # most frequent element
# [("d", 5)]

11.判断两个字符串是否为Anagrams

Anagrams的含义为两个单词中，每个英文单词（不含大小写）出现的次数相同，使用Counter类判断两个字符串是否为Anagrams。

from collections import Counter
 
str_1, str_2, str_3 = "acbde", "abced", "abcda"
cnt_1, cnt_2, cnt_3  = Counter(str_1), Counter(str_2), Counter(str_3)
 
if cnt_1 == cnt_2:
    print("1 and 2 anagram")
if cnt_1 == cnt_3:
    print("1 and 3 anagram")
 
# output
# 1 and 2 anagram

12. 使用try-except-else-block模块

except获取异常处理：

a, b = 1,0
 
try:
    print(a/b)
    # exception raised when b is 0
except ZeroDivisionError:
    print("division by zero")
else:
    print("no exceptions raised")
finally:
    print("Run this always")
 
# output
# division by zero
# Run this always

13. 使用枚举函数得到key/value对

my_list = ["a", "b", "c", "d", "e"]
 
for index, value in enumerate(my_list):
    print("{0}: {1}".format(index, value))
 
# 0: a
# 1: b
# 2: c
# 3: d
# 4: e

14.检查对象的内存使用情况

import sys
 
num = 21
 
print(sys.getsizeof(num))
 
# In Python 2, 24
# In Python 3, 28

15.合并字典

dict_1 = {"apple": 9, "banana": 6}
dict_2 = {"banana": 4, "orange": 8}
 
combined_dict = {**dict_1, **dict_2}
 
print(combined_dict)
# Output
# {"apple": 9, "banana": 4, "orange": 8}

16.计算执行一段代码所花费的时间

使用time类计算运行一段代码所花费的时间：

import time
 
start_time = time.time()
# Code to check follows
for i in range(10**5):
    a, b = 1,2
    c = a+ b
# Code to check ends
end_time = time.time()
time_taken_in_micro = (end_time- start_time)*(10**6)
 
print(time_taken_in_micro)
 
# output
# 18770.217895507812

17. 列表展开

from iteration_utilities import deepflatten
 
# if you only have one depth nested_list, use this
def flatten(l):
  return [item for sublist in l for item in sublist]
 
l = [[1,2,3],[3]]
print(flatten(l))
# [1, 2, 3, 3]
 
# if you don"t know how deep the list is nested
l = [[1,2,3],[4,[5],[6,7]],[8,[9,[10]]]]
 
print(list(deepflatten(l, depth=3)))
# [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]

18. 列表采样

import random
 
my_list = ["a", "b", "c", "d", "e"]
num_samples = 2
 
samples = random.sample(my_list,num_samples)
print(samples)
# [ "a", "e"] this will have any 2 random values

19.数字化

将整数转化成数字列表

num = 123456
 
# using map
list_of_digits = list(map(int, str(num)))
 
print(list_of_digits)
# [1, 2, 3, 4, 5, 6]
 
# using list comprehension
list_of_digits = [int(x) for x in str(num)]
 
print(list_of_digits)
# [1, 2, 3, 4, 5, 6]

20.检查列表元素的唯一性

检查列表中每个元素是否为唯一的：

def unique(l):
    if len(l)==len(set(l)):
        print("All elements are unique")
    else:
        print("List has duplicates")
 
unique([1,2,3,4])
# All elements are unique
 
unique([1,1,2,3])
# List has duplicates

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关键词： 字符串查找 使用情况 第一个字母 重复打印