使用Python获取字典键对应值的两种方法
目录
当知道字典的键时:当不知道字典的键时:附:字典dic最大值对应的键总结有两种方法
当知道字典的键时:
unit_rooms={ 3:{301:[1,80],302:[1,80],303:[2,90],304:[2,90]},
4:{401:[1,80],402:[1,80],403:[2,90],404:[2,90]},
5:{501:[1,80],502:[1,80],503:[2,90],504:[2,90]}
}
for i in range(3,6):
rooms=unit_rooms[i]
print(rooms)运行结果:
当不知道字典的键时:
unit_rooms = {3:{301:[1,80],302:[1,80],303:[2,90],304:[2,90]},
4:{401:[1,80],402:[1,80],403:[2,90],404:[2,90]},
5:{501:[1,80],502:[1,80],503:[2,90],504:[2,90]}
}
for rooms in unit_rooms.values():
print(rooms)运行结果:
获取字典的值:
for value in DictName.values(): # value的名字可以自行另取 # DictName是要遍历的字典的名称 # .values():是固定的用法
获取键值:
for k,v in DictName.items(): #遍历字典的键值对,k对应键,v对应值 #k,v 的名字可以自己取,DictName是字典名
unit_rooms = {3:{301:[1,80],302:[1,80],303:[2,90],304:[2,90]},
4:{401:[1,80],402:[1,80],403:[2,90],404:[2,90]},
5:{501:[1,80],502:[1,80],503:[2,90],504:[2,90]}
}
for sub_dict in unit_rooms.values():
# 遍历大字典的值,即小字典sub_dict
for room,info in sub_dict.items():
print("房间号:%d,方向:%d,面积:%d"%(room,info[0],info[1]))运行结果:
方向1代表南北,方向2代表东西
把数字替换掉:
unit_rooms = {3:{301:[1,80],302:[1,80],303:[2,90],304:[2,90]},
4:{401:[1,80],402:[1,80],403:[2,90],404:[2,90]},
5:{501:[1,80],502:[1,80],503:[2,90],504:[2,90]}
}
for sub_dict in unit_rooms.values():
for room,info in sub_dict.items():
dire = ["", "南北", "东西"]
#建立一个列表,第0个元素为空,第1个元素为"南北",第2个元素为"东西"
print(dire[info[0]])举例:
unit_rooms = {3:{301:[1,80],302:[1,80],303:[2,90],304:[2,90]},
4:{401:[1,80],402:[1,80],403:[2,90],404:[2,90]},
5:{501:[1,80],502:[1,80],503:[2,90],504:[2,90]}
}
for sub_dict in unit_rooms.values():
for room,info in sub_dict.items():
dire = ["", "南北", "东西"]
print("户室号:%d 朝向:%s 面积:%d" % (room,dire[info[0]],info[1])) 运行结果:
附:字典dic最大值对应的键
步骤:(1)用max()函数找出最大的值maxValue;(2)套用一的自定义函数
def getKey(dic, value):
if value not in dic.values():
return None
result = set()
for key in dic:
if dic[key]==value:
result.add(key)
return result
dic = {"a":2, "b":1, "c":10, "d":10}
maxValue=max(dic.values())
result = getKey(dic,maxValue)
>> {"c","d"}
总结
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