当前速递!使用python爬虫实现子域名探测问题
来源:脚本之家    时间:2022-07-07 09:59:49
目录
前言一、爬虫1.ip1382.bing二、通过字典进行子域名爆破三、python爬虫操作步骤1.写出请求头headers与目标网站url2.生成请求3.抓取数据4.分析源码,截取标签中内容四、爬虫一些总结

前言

意义:子域名枚举是为一个或多个域查找子域的过程,它是信息收集阶段的重要组成部分。
实现方法:使用爬虫与字典爆破。

一、爬虫

1.ip138

def search_2(domain):
    res_list = []
    headers = {
        "Accept": "*/*",
        "Accept-Language": "en-US,en;q=0.8",
        "Cache-Control": "max-age=0",
        "User-Agent": "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.116 Safari/537.36",
        "Connection": "keep-alive",
        "Referer": "http://www.baidu.com/"
    }
    results = requests.get("https://site.ip138.com/" + domain + "/domain.htm", headers=headers)
    soup = BeautifulSoup(results.content, "html.parser")
    job_bt = soup.findAll("p")

    try:
        for i in job_bt:
            link = i.a.get("href")
            linkk = link[1:-1]
            res_list.append(linkk)
            print(linkk)
    except:
        pass
    print(res_list[:-1])
if __name__ == "__main__":
    search_2("jd.com")

返回结果:

2.bing

def search_1(site):
    Subdomain = []
    headers = {
        "Accept": "*/*",
        "Accept-Language": "en-US,en;q=0.8",
        "Cache-Control": "max-age=0",
        "User-Agent": "Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.116 Safari/537.36",
        "Connection": "keep-alive",
        "Referer": "http://www.baidu.com/"
    }
    for i in range(1, 16):
        url = "https://cn.bing.com/search?q=site%3A" + site + "&go=Search&qs=ds&first=" + str(
            (int(i) - 1) * 10) + "&FORM=PERE"
        # conn = requests.session()
        # conn.get("http://cn.bing.com", headers=headers)
        # html = conn.get(url, stream=True, headers=headers)
        html = requests.get(url, stream=True, headers=headers)
        soup = BeautifulSoup(html.content, "html.parser")
        # print(soup)
        job_bt = soup.findAll("h2")
        for i in job_bt:
            link = i.a.get("href")
            print(link)
            if link in Subdomain:
                pass
            else:
                Subdomain.append(link)
    print(Subdomain)
if __name__ == "__main__":
    search_1("jd.com")

返回结果:


【资料图】

二、通过字典进行子域名爆破

def dict(url):
    for dict in open("dic.txt"):  # 这里用到子域名字典文件dic.txt
        dict = dict.replace("\n", "")
        zym_url = dict + "." + url
        try:
            ip = socket.gethostbyname(zym_url)
            print(zym_url + "-->" + ip)
            time.sleep(0.1)
        except Exception as e:
            # print(zym_url + "-->" + ip + "--error")
            time.sleep(0.1)
if __name__ == "__main__":
    dict("jd.com")

返回结果:

三、python爬虫操作步骤

1.写出请求头headers与目标网站url

headers = {
        "User-Agent": "Mozilla/5.0 (Windows NT 10.0) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/42.0.2311.135 Safari/537.36 Edge/12.10240"
    }
url = "https://site.ip138.com/"

2.生成请求

get:res = requests.get(url + domain, headers=headers)
post:res = requests.post(url + domain, headers=headers, data=data)

3.抓取数据

soup = BeautifulSoup(res.content, "html.parser")  # 以html解析器解析res的内容

此时print(soup),返回结果:

4.分析源码,截取标签中内容

1.通过分析源码,确定需要提取p标签中的内容:

job_bt = soup.findAll("p")

此时print(job_bt),返回结果:

2.继续提取a标签内属性为href的值:

try:
    for i in job_bt:
        link = i.a.get("href")
        linkk = link[1:-1]
        res_list.append(linkk)
        print(linkk)
except:
    pass

得结果:

3.再进行截取:

res_list[:-1]

得结果:

四、爬虫一些总结

1.抓取数据,生成soup

soup = BeautifulSoup(res.content, "html.parser")  # 以html解析器解析res的内容

2.从文档中获取所有文字内容

print(soup.get_text())

3.从文档中找到所有< a >标签的链接

for link in soup.find_all("a"):
    print(link.get("href"))

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